6=3x^2-26=3x^2-2

Solution for 6=3x^2-26=3x^2-2 equation:

6=3x^2-26=3x^2-2

We move all terms to the left:

6-(3x^2-26)=0

We get rid of parentheses

-3x^2+26+6=0

We add all the numbers together, and all the variables

-3x^2+32=0

a = -3; b = 0; c = +32;
Δ = b2-4ac
Δ = 02-4·(-3)·32
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{6}}{2*-3}=\frac{0-8\sqrt{6}}{-6}
=-\frac{8\sqrt{6}}{-6}
=-\frac{4\sqrt{6}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{6}}{2*-3}=\frac{0+8\sqrt{6}}{-6}
=\frac{8\sqrt{6}}{-6}
=\frac{4\sqrt{6}}{-3}
$